3x^2-5x-62=0

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Solution for 3x^2-5x-62=0 equation: 



3x^2-5x-62=0

a = 3; b = -5; c = -62;
Δ = b2-4ac
Δ = -52-4·3·(-62)
Δ = 769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{769}}{2*3}=\frac{5-\sqrt{769}}{6}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{769}}{2*3}=\frac{5+\sqrt{769}}{6}
$

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